-121y^2+8y+32=0

Solution for -121y^2+8y+32=0 equation:

-121y^2+8y+32=0

a = -121; b = 8; c = +32;
Δ = b2-4ac
Δ = 82-4·(-121)·32
Δ = 15552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15552}=\sqrt{5184*3}=\sqrt{5184}*\sqrt{3}=72\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-72\sqrt{3}}{2*-121}=\frac{-8-72\sqrt{3}}{-242}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+72\sqrt{3}}{2*-121}=\frac{-8+72\sqrt{3}}{-242}
$